Page 49 - Energize September 2022
P. 49

TECHNICAL


        PF and harmonics: Compensation


        and correction





        Efficient operation requires that the maximum amount of power is delivered to the load for a given
        circuit capacity. The PF of a load can affect this capability and result in less power delivery than the
        network is capable of. PF problems can be corrected in various ways.


                                                   By Mike Rycroft, Energize



            ower Factor (PF) is the ratio of true power to apparent
            power in a circuit or distribution system. Any AC circuit
       Pconsists of real, reactive, harmonic and apparent (total)
        power. True power is the power, in W or kW, used by motors,
        lights and other devices to produce useful work. Reactive power
        is the power, in VAR or kVAR, stored and released by inductors
        and capacitors.
           Reactive power shows up as a phase displacement between the
        current and voltage waveforms. Harmonic power is power, in VA or   Figure 1: Effect of reactive components on current (Electrical 4U)
        kVA, lost to harmonic distortion. Apparent power is the power, in
        VA or kVA, which is the vector sum of true power, reactive power
        and harmonic power. Apparent power is not a simple summation   the voltage or lag the voltage as shown in Figure 1. Most PF
        but a vector summation.                                problems encountered in networks involve a lagging PF due to
           The PF problem is that less power is delivered to the load, and   inductive loads.
        a higher current is required to deliver the same power as the ideal   The PF of these leading or lagging loads is an expression of the
        case (where PF = 1). Higher current means higher I R losses, larger   amount that the current was out of phase with the voltage, hence
                                             2
        transformers, cables and switch gear for the same power delivered.   the term displacement PF. By applying the same magnitude of
        Generators are also affected by low PF circuits.       corrective PF (in the case of lagging PF, a leading PF device needs to
                                                               be connected and vice versa) the original poor PF is cancelled out
        PF and linear electric loads                           and the overall PF improves. On most sites a practical target PF is
        Linear electrical loads fall into one of three categories from a PF   between 0,95 and 0,99 at 50 Hz.
        perspective:
        •  Resistive – These are loads which display resistive characteristics   The real power delivered to the load is the product of voltage and
         only. There is no inductance or capacitance to impact on PF. With   current, and because the current is out of phase with the voltage
         resistive loads the voltage and the current are in phase, meaning   this is given by:
         that no PF correction is required. Examples of these loads are
         incandescent light bulbs and heating elements.        P r = V*I*Cos θ                                 (1)
        •  Inductive – These are loads which display both resistive and
         inductive characteristics. The inductive component of the load   where θ is the phase angle between voltage (V) and current (I).
         causes the current to lag behind the voltage, hence the term
         lagging PF. These inductive loads are very common in industry   The apparent power is the product of the values of voltage and
         and examples are AC motors, lighting ballasts and induction   current, ignoring the phase angle:
         furnaces.
        •  Capacitive – These are loads which display both resistive and   P a = V*I                           (2)
         capacitive characteristics. The capacitive component of the load
         causes the current to lead the voltage, hence the term leading   PF is defined as the ratio of real power to apparent power and is
         PF. These capacitive loads are uncommon. An example is an over-  equal to the cosine of the phase angle.
         excited synchronous motor or capacitor.
                                                               PF disp = Cos θ                                 (3)
        Reactive components cause the current flowing in the circuit
        to be out of phase with the voltage i.e., the current may lead   This is referred to as displacement PF.



                                                  energize | September 2022 | 47
   44   45   46   47   48   49   50   51   52   53   54